pub broadcast proof fn lemma_disjoint_tuple_left<U1: SpecParser, V1: SpecParser, U: SpecParser>(
tuple: Pair<U1, V1>,
other: U,
)Expand description
requires
disjoint_domains(tuple.0, other),ensures#[trigger] disjoint_domains(tuple, other),A tuple parser is disjoint from another parser if its first component is.