pub broadcast proof fn lemma_disjoint_repeat_left<A: SpecParser, B: SpecParser, P: SpecParser>(
repeat: Repeat<A, B>,
p: P,
)Expand description
requires
disjoint_domains(repeat.0, p),disjoint_domains(repeat.1, p),ensures#[trigger] disjoint_domains(repeat, p),A Repeat<A, B> parser is disjoint from another parser if both A and B are.