pub broadcast proof fn lemma_disjoint_repeat<P: SpecParser, A: SpecParser, B: SpecParser>(
p: P,
repeat: Repeat<A, B>,
)Expand description
requires
disjoint_domains(p, repeat.0),disjoint_domains(p, repeat.1),ensures#[trigger] disjoint_domains(p, repeat),A Repeat<A, B> parser is disjoint from another parser if both A and B are.